b^2-20=b

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Solution for b^2-20=b equation:


Simplifying
b2 + -20 = b

Reorder the terms:
-20 + b2 = b

Solving
-20 + b2 = b

Solving for variable 'b'.

Reorder the terms:
-20 + -1b + b2 = b + -1b

Combine like terms: b + -1b = 0
-20 + -1b + b2 = 0

Factor a trinomial.
(-4 + -1b)(5 + -1b) = 0

Subproblem 1

Set the factor '(-4 + -1b)' equal to zero and attempt to solve: Simplifying -4 + -1b = 0 Solving -4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1b = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1b = 0 + 4 -1b = 0 + 4 Combine like terms: 0 + 4 = 4 -1b = 4 Divide each side by '-1'. b = -4 Simplifying b = -4

Subproblem 2

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Solution

b = {-4, 5}

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